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Two way linked list algorithm 2022

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Doubly Linked List


In this tutorial, you will learn about the doubly linke list and its implementation in Python, Java, C, and C++.


Nội dung chính


  • Doubly Linked List

  • Representation of Doubly Linked List

  • Insertion on a Doubly Linked List

  • 1. Insertion the Beginning

  • Code for Insertion the Beginning

  • 2. Insertion in between two nodes

  • Code for Insertion in between two Nodes

  • 3. Insertion the End

  • Code for Insertion the End

  • Deletion from a Doubly Linked List

  • 1. Delete the First Node of Doubly Linked List

  • 2. Deletion of the Inner Node

  • 3. Delete the Last Node of Doubly Linked List

  • Doubly Linked List Code in Python, Java, C, and C++

  • Doubly Linked List Complexity

  • Doubly Linked List Applications

  • Singly Linked List Vs Doubly Linked List

  • Table of Contents


  • A doubly linked list is a type of linked list in which each node consists of 3 components:


    • *prev – address of the previous node

    • data – data item

    • *next – address of next node

    A doubly linked list nodeA doubly linked list node


    Note: Before you proceed further, make sure to learn about pointers and structs.


    Representation of Doubly Linked List


    Let’s see how we can represent a doubly linked list on an algorithm/code. Suppose we have a doubly linked list:


    Newly created doubly linked listNewly created doubly linked list


    Here, the single node is represented as


    struct node

    int data;

    struct node *next;

    struct node *prev;


    Each struct node has a data item, a pointer to the previous struct node, and a pointer to the next struct node.


    Now we will create a simple doubly linked list with three items to understand how this works.


    /* Initialize nodes */

    struct node *head;

    struct node *one = NULL;

    struct node *two = NULL;

    struct node *three = NULL;

    /* Allocate memory */

    one = malloc(sizeof(struct node));

    two = malloc(sizeof(struct node));

    three = malloc(sizeof(struct node));

    /* Assign data values */

    one->data = 1;

    two->data = 2;

    three->data = 3;

    /* Connect nodes */

    one->next = two;

    one->prev = NULL;

    two->next = three;

    two->prev = one;

    three->next = NULL;

    three->prev = two;

    /* Save address of first node in head */

    head = one;


    In the above code, one, two, and three are the nodes with data items 1, 2, and 3 respectively.


    • For node one: next stores the address of two and prev stores null (there is no node before it)

    • For node two: next stores the address of three and prev stores the address of one

    • For node three: next stores null (there is no node after it) and prev stores the address of two.

    Note: In the case of the head node, prev points to null, and in the case of the tail pointer, next points to null. Here, one is a head node and three is a tail node.


    Insertion on a Doubly Linked List


    Pushing a node to a doubly-linked list is similar to pushing a node to a linked list, but extra work is required to handle the pointer to the previous node.


    We can insert elements 3 different positions of a doubly-linked list:


  • Insertion the beginning

  • Insertion in-between nodes

  • Insertion the End

  • Suppose we have a double-linked list with elements 1, 2, and 3.


    Original doubly linked listOriginal doubly linked list


    1. Insertion the Beginning


    Let’s add a node with value 6 the beginning of the doubly linked list we made above.


    1. Create a new node


    • allocate memory for newNode

    • assign the data to newNode.

    New nodeNew node


    2. Set prev and next pointers of new node


    • point next of newNode to the first node of the doubly linked list

    • point prev to null

    Reorganize the pointersReorganize the pointers (changes are denoted by purple arrows)


    3. Make new node as head node


    • Point prev of the first node to newNode (now the previous head is the second node)

    • Point head to newNode

    Reorganize the pointersReorganize the pointers


    Code for Insertion the Beginning


    // insert node the front

    void insertFront(struct Node** head, int data)

    // allocate memory for newNode

    struct Node* newNode = new Node;

    // assign data to newNode

    newNode->data = data;

    // point next of newNode to the first node of the doubly linked list

    newNode->next = (*head);

    // point prev to NULL

    newNode->prev = NULL;

    // point previous of the first node (now first node is the second node) to newNode

    if ((*head) != NULL)

    (*head)->prev = newNode;

    // head points to newNode

    (*head) = newNode;


    2. Insertion in between two nodes


    Let’s add a node with value 6 after node with value 1 in the doubly linked list.


    1. Create a new node


    • allocate memory for newNode

    • assign the data to newNode.

    New nodeNew node


    2. Set the next pointer of new node and previous node


    • assign the value of next from previous node to the next of newNode

    • assign the address of newNode to the next of previous node

    Reorganize the pointersReorganize the pointers


    3. Set the prev pointer of new node and the next node


    • assign the value of prev of next node to the prev of newNode

    • assign the address of newNode to the prev of next node

    Reorganize the pointersReorganize the pointers


    The final doubly linked list is after this insertion is:


    Final listFinal list


    Code for Insertion in between two Nodes


    // insert a node after a specific node

    void insertAfter(struct Node* prev_node, int data)

    // check if previous node is NULL

    if (prev_node == NULL)

    cout << “previous node cannot be NULL”;

    return;


    // allocate memory for newNode

    struct Node* newNode = new Node;

    // assign data to newNode

    newNode->data = data;

    // set next of newNode to next of prev node

    newNode->next = prev_node->next;

    // set next of prev node to newNode

    prev_node->next = newNode;

    // set prev of newNode to the previous node

    newNode->prev = prev_node;

    // set prev of newNode’s next to newNode

    if (newNode->next != NULL)

    newNode->next->prev = newNode;


    3. Insertion the End


    Let’s add a node with value 6 the end of the doubly linked list.


    1. Create a new node


    New nodeNew node


    2. Set prev and next pointers of new node and the previous node


    If the linked list is empty, make the newNode as the head node. Otherwise, traverse to the end of the doubly linked list and


    Reorganize the pointersReorganize the pointers


    The final doubly linked list looks like this.


    The final listThe final list


    Code for Insertion the End


    // insert a newNode the end of the list

    void insertEnd(struct Node** head, int data)

    // allocate memory for node

    struct Node* newNode = new Node;

    // assign data to newNode

    newNode->data = data;

    // assign NULL to next of newNode

    newNode->next = NULL;

    // store the head node temporarily (for later use)

    struct Node* temp = *head;

    // if the linked list is empty, make the newNode as head node

    if (*head == NULL)

    newNode->prev = NULL;

    *head = newNode;

    return;


    // if the linked list is not empty, traverse to the end of the linked list

    while (temp->next != NULL)

    temp = temp->next;

    // now, the last node of the linked list is temp

    // point the next of the last node (temp) to newNode.

    temp->next = newNode;

    // assign prev of newNode to temp

    newNode->prev = temp;


    Deletion from a Doubly Linked List


    Similar to insertion, we can also delete a node from 3 different positions of a doubly linked list.


    Suppose we have a double-linked list with elements 1, 2, and 3.


    Original doubly linked listOriginal doubly linked list


    1. Delete the First Node of Doubly Linked List


    If the node to be deleted (i.e. del_node) is the beginning


    Reset value node after the del_node (i.e. node two)


    Reorganize the pointersReorganize the pointers


    Finally, không lấy phí the memory of del_node. And, the linked will look like this


    Final listFinal list


    Code for Deletion of the First Node


    if (*head == del_node)

    *head = del_node->next;

    if (del_node->prev != NULL)

    del_node->prev->next = del_node->next;

    không lấy phí(del);


    2. Deletion of the Inner Node


    If del_node is an inner node (second node), we must have to reset the value of next and prev of the nodes before and after the del_node.


    For the node before the del_node (i.e. first node)


    Assign the value of next of del_node to the next of the first node.


    For the node after the del_node (i.e. third node)


    Assign the value of prev of del_node to the prev of the third node.


    Reorganize the pointersReorganize the pointers


    Finally, we will không lấy phí the memory of del_node. And, the final doubly linked list looks like this.


    Final listFinal list


    Code for Deletion of the Inner Node


    if (del_node->next != NULL)

    del_node->next->prev = del_node->prev;

    if (del_node->prev != NULL)

    del_node->prev->next = del_node->next;


    3. Delete the Last Node of Doubly Linked List


    In this case, we are deleting the last node with value 3 of the doubly linked list.


    Here, we can simply delete the del_node and make the next of node before del_node point to NULL.


    Reorganize the pointersReorganize the pointers


    The final doubly linked list looks like this.


    Final listFinal list


    Code for Deletion of the Last Node


    if (del_node->prev != NULL)

    del_node->prev->next = del_node->next;


    Here, del_node ->next is NULL so del_node->prev->next = NULL.


    Note: We can also solve this using the first condition (for the node before del_node) of the second case (Delete the inner node).


    Doubly Linked List Code in Python, Java, C, and C++


    PythonJavaCC++import gc

    # node creation

    class Node:

    def __init__(self, data):

    self.data = data

    self.next = None

    self.prev = None

    class DoublyLinkedList:

    def __init__(self):

    self.head = None

    # insert node the front

    def insert_front(self, data):

    # allocate memory for newNode and assign data to newNode

    new_node = Node(data)

    # make newNode as a head

    new_node.next = self.head

    # assign null to prev (prev is already none in the constructore)

    # previous of head (now head is the second node) is newNode

    if self.head is not None:

    self.head.prev = new_node

    # head points to newNode

    self.head = new_node

    # insert a node after a specific node

    def insert_after(self, prev_node, data):

    # check if previous node is null

    if prev_node is None:

    print(“previous node cannot be null”)

    return

    # allocate memory for newNode and assign data to newNode

    new_node = Node(data)

    # set next of newNode to next of prev node

    new_node.next = prev_node.next

    # set next of prev node to newNode

    prev_node.next = new_node

    # set prev of newNode to the previous node

    new_node.prev = prev_node

    # set prev of newNode’s next to newNode

    if new_node.next:

    new_node.next.prev = new_node

    # insert a newNode the end of the list

    def insert_end(self, data):

    # allocate memory for newNode and assign data to newNode

    new_node = Node(data)

    # assign null to next of newNode (already done in constructor)

    # if the linked list is empty, make the newNode as head node

    if self.head is None:

    self.head = new_node

    return

    # store the head node temporarily (for later use)

    temp = self.head

    # if the linked list is not empty, traverse to the end of the linked list

    while temp.next:

    temp = temp.next

    # now, the last node of the linked list is temp

    # assign next of the last node (temp) to newNode

    temp.next = new_node

    # assign prev of newNode to temp

    new_node.prev = temp

    return

    # delete a node from the doubly linked list

    def deleteNode(self, dele):

    # if head or del is null, deletion is not possible

    if self.head is None or dele is None:

    return

    # if del_node is the head node, point the head pointer to the next of del_node

    if self.head == dele:

    self.head = dele.next

    # if del_node is not the last node, point the prev of node next to del_node to the previous of del_node

    if dele.next is not None:

    dele.next.prev = dele.prev

    # if del_node is not the first node, point the next of the previous node to the next node of del_node

    if dele.prev is not None:

    dele.prev.next = dele.next

    # không lấy phí the memory of del_node

    gc.collect()

    # print the doubly linked list

    def display_list(self, node):

    while node:

    print(node.data, end=”->”)

    last = node

    node = node.next

    # initialize an empty node

    d_linked_list = DoublyLinkedList()

    d_linked_list.insert_end(5)

    d_linked_list.insert_front(1)

    d_linked_list.insert_front(6)

    d_linked_list.insert_end(9)

    # insert 11 after head

    d_linked_list.insert_after(d_linked_list.head, 11)

    # insert 15 after the seond node

    d_linked_list.insert_after(d_linked_list.head.next, 15)

    d_linked_list.display_list(d_linked_list.head)

    # delete the last node

    d_linked_list.deleteNode(d_linked_list.head.next.next.next.next.next)

    print()

    d_linked_list.display_list(d_linked_list.head)public class DoublyLinkedList

    // node creation

    Node head;

    class Node

    int data;

    Node prev;

    Node next;

    Node(int d)

    data = d;


    // insert node the front

    public void insertFront(int data)

    // allocate memory for newNode and assign data to newNode

    Node newNode = new Node(data);

    // make newNode as a head

    newNode.next = head;

    // assign null to prev of newNode

    newNode.prev = null;

    // previous of head (now head is the second node) is newNode

    if (head != null)

    head.prev = newNode;

    // head points to newNode

    head = newNode;


    // insert a node after a specific node

    public void insertAfter(Node prev_node, int data)

    // check if previous node is null

    if (prev_node == null)

    System.out.println(“previous node cannot be null”);

    return;


    // allocate memory for newNode and assign data to newNode

    Node new_node = new Node(data);

    // set next of newNode to next of prev node

    new_node.next = prev_node.next;

    // set next of prev node to newNode

    prev_node.next = new_node;

    // set prev of newNode to the previous node

    new_node.prev = prev_node;

    // set prev of newNode’s next to newNode

    if (new_node.next != null)

    new_node.next.prev = new_node;


    // insert a newNode the end of the list

    void insertEnd(int data)

    // allocate memory for newNode and assign data to newNode

    Node new_node = new Node(data);

    // store the head node temporarily (for later use)

    Node temp = head;

    // assign null to next of newNode

    new_node.next = null;

    // if the linked list is empty, make the newNode as head node

    if (head == null)

    new_node.prev = null;

    head = new_node;

    return;


    // if the linked list is not empty, traverse to the end of the linked list

    while (temp.next != null)

    temp = temp.next;

    // assign next of the last node (temp) to newNode

    temp.next = new_node;

    // assign prev of newNode to temp

    new_node.prev = temp;


    // delete a node from the doubly linked list

    void deleteNode(Node del_node) del_node == null)

    return;


    // if del_node is the head node, point the head pointer to the next of del_node

    if (head == del_node)

    head = del_node.next;


    // if del_node is not the last node, point the prev of node next to del_node

    // to the previous of del_node

    if (del_node.next != null)

    del_node.next.prev = del_node.prev;


    // if del_node is not the first node, point the next of the previous node to the

    // next node of del_node

    if (del_node.prev != null)

    del_node.prev.next = del_node.next;


    // print the doubly linked list

    public void printlist(Node node)

    Node last = null;

    while (node != null)

    System.out.print(node.data + “->”);

    last = node;

    node = node.next;


    System.out.println();


    public static void main(String[] args)

    DoublyLinkedList doubly_ll = new DoublyLinkedList();

    doubly_ll.insertEnd(5);

    doubly_ll.insertFront(1);

    doubly_ll.insertFront(6);

    doubly_ll.insertEnd(9);

    // insert 11 after head

    doubly_ll.insertAfter(doubly_ll.head, 11);

    // insert 15 after the seond node

    doubly_ll.insertAfter(doubly_ll.head.next, 11);

    doubly_ll.printlist(doubly_ll.head);

    // delete the last node

    doubly_ll.deleteNode(doubly_ll.head.next.next.next.next.next);

    doubly_ll.printlist(doubly_ll.head);


    #include <stdio.h>

    #include <stdlib.h>

    // node creation

    struct Node

    int data;

    struct Node* next;

    struct Node* prev;

    ;

    // insert node the front

    void insertFront(struct Node** head, int data)

    // allocate memory for newNode

    struct Node* newNode = (struct Node*)malloc(sizeof(struct Node));

    // assign data to newNode

    newNode->data = data;

    // make newNode as a head

    newNode->next = (*head);

    // assign null to prev

    newNode->prev = NULL;

    // previous of head (now head is the second node) is newNode

    if ((*head) != NULL)

    (*head)->prev = newNode;

    // head points to newNode

    (*head) = newNode;


    // insert a node after a specific node

    void insertAfter(struct Node* prev_node, int data)

    // check if previous node is null

    if (prev_node == NULL)

    printf(“previous node cannot be null”);

    return;


    // allocate memory for newNode

    struct Node* newNode = (struct Node*)malloc(sizeof(struct Node));

    // assign data to newNode

    newNode->data = data;

    // set next of newNode to next of prev node

    newNode->next = prev_node->next;

    // set next of prev node to newNode

    prev_node->next = newNode;

    // set prev of newNode to the previous node

    newNode->prev = prev_node;

    // set prev of newNode’s next to newNode

    if (newNode->next != NULL)

    newNode->next->prev = newNode;


    // insert a newNode the end of the list

    void insertEnd(struct Node** head, int data)

    // allocate memory for node

    struct Node* newNode = (struct Node*)malloc(sizeof(struct Node));

    // assign data to newNode

    newNode->data = data;

    // assign null to next of newNode

    newNode->next = NULL;

    // store the head node temporarily (for later use)

    struct Node* temp = *head;

    // if the linked list is empty, make the newNode as head node

    if (*head == NULL)

    newNode->prev = NULL;

    *head = newNode;

    return;


    // if the linked list is not empty, traverse to the end of the linked list

    while (temp->next != NULL)

    temp = temp->next;

    // now, the last node of the linked list is temp

    // assign next of the last node (temp) to newNode

    temp->next = newNode;

    // assign prev of newNode to temp

    newNode->prev = temp;


    // delete a node from the doubly linked list

    void deleteNode(struct Node** head, struct Node* del_node) del_node == NULL)

    return;

    // if del_node is the head node, point the head pointer to the next of del_node

    if (*head == del_node)

    *head = del_node->next;

    // if del_node is not the last node, point the prev of node next to del_node to the previous of del_node

    if (del_node->next != NULL)

    del_node->next->prev = del_node->prev;

    // if del_node is not the first node, point the next of the previous node to the next node of del_node

    if (del_node->prev != NULL)

    del_node->prev->next = del_node->next;

    // không lấy phí the memory of del_node

    không lấy phí(del_node);


    // print the doubly linked list

    void displayList(struct Node* node)

    struct Node* last;

    while (node != NULL)

    printf(“%d->”, node->data);

    last = node;

    node = node->next;


    if (node == NULL)

    printf(“NULLn”);


    int main()

    // initialize an empty node

    struct Node* head = NULL;

    insertEnd(&head, 5);

    insertFront(&head, 1);

    insertFront(&head, 6);

    insertEnd(&head, 9);

    // insert 11 after head

    insertAfter(head, 11);

    // insert 15 after the seond node

    insertAfter(head->next, 15);

    displayList(head);

    // delete the last node

    deleteNode(&head, head->next->next->next->next->next);

    displayList(head);

    #include <iostream>

    using namespace std;

    // node creation

    struct Node

    int data;

    struct Node* next;

    struct Node* prev;

    ;

    // insert node the front

    void insertFront(struct Node** head, int data)

    // allocate memory for newNode

    struct Node* newNode = new Node;

    // assign data to newNode

    newNode->data = data;

    // make newNode as a head

    newNode->next = (*head);

    // assign null to prev

    newNode->prev = NULL;

    // previous of head (now head is the second node) is newNode

    if ((*head) != NULL)

    (*head)->prev = newNode;

    // head points to newNode

    (*head) = newNode;


    // insert a node after a specific node

    void insertAfter(struct Node* prev_node, int data)

    // check if previous node is null

    if (prev_node == NULL)

    cout << “previous node cannot be null”;

    return;


    // allocate memory for newNode

    struct Node* newNode = new Node;

    // assign data to newNode

    newNode->data = data;

    // set next of newNode to next of prev node

    newNode->next = prev_node->next;

    // set next of prev node to newNode

    prev_node->next = newNode;

    // set prev of newNode to the previous node

    newNode->prev = prev_node;

    // set prev of newNode’s next to newNode

    if (newNode->next != NULL)

    newNode->next->prev = newNode;


    // insert a newNode the end of the list

    void insertEnd(struct Node** head, int data)

    // allocate memory for node

    struct Node* newNode = new Node;

    // assign data to newNode

    newNode->data = data;

    // assign null to next of newNode

    newNode->next = NULL;

    // store the head node temporarily (for later use)

    struct Node* temp = *head;

    // if the linked list is empty, make the newNode as head node

    if (*head == NULL)

    newNode->prev = NULL;

    *head = newNode;

    return;


    // if the linked list is not empty, traverse to the end of the linked list

    while (temp->next != NULL)

    temp = temp->next;

    // now, the last node of the linked list is temp

    // assign next of the last node (temp) to newNode

    temp->next = newNode;

    // assign prev of newNode to temp

    newNode->prev = temp;


    // delete a node from the doubly linked list

    void deleteNode(struct Node** head, struct Node* del_node)

    // if head or del is null, deletion is not possible

    if (*head == NULL

    // print the doubly linked list

    void displayList(struct Node* node)

    struct Node* last;

    while (node != NULL)

    cout << node->data << “->”;

    last = node;

    node = node->next;


    if (node == NULL)

    cout << “NULLn”;


    int main()

    // initialize an empty node

    struct Node* head = NULL;

    insertEnd(&head, 5);

    insertFront(&head, 1);

    insertFront(&head, 6);

    insertEnd(&head, 9);

    // insert 11 after head

    insertAfter(head, 11);

    // insert 15 after the seond node

    insertAfter(head->next, 15);

    displayList(head);

    // delete the last node

    deleteNode(&head, head->next->next->next->next->next);

    displayList(head);


    Doubly Linked List Complexity


    Doubly Linked List ComplexityTime ComplexitySpace ComplexityInsertion OperationO(1) or O(n)O(1)Deletion OperationO(1)O(1)


    1. Complexity of Insertion Operation


    • The insertion operations that do not require traversal have the time complexity of O(1).

    • And, insertion that requires traversal has time complexity of O(n).

    • The space complexity is O(1).

    2. Complexity of Deletion Operation


    • All deletion operations run with time complexity of O(1).

    • And, the space complexity is O(1).

    Doubly Linked List Applications


  • Redo and undo functionality in software.

  • Forward and backward navigation in browsers.

  • For navigation systems where forward and backward navigation is required.

  • Singly Linked List Vs Doubly Linked List


    Singly Linked ListDoubly Linked ListEach node consists of a data value and a pointer to the next node.Each node consists of a data value, a pointer to the next node, and a pointer to the previous node.Traversal can occur in one way only (forward direction).Traversal can occur in both ways.It requires less space.It requires more space because of an extra pointer.It can be implemented on the stack.It has multiple usages. It can be implemented on the stack, heap, and binary tree.


    Table of Contents


    • Definition

    • Representation of Doubly Linked List

    • Insertion the Beginning of doubly linked list

    • Insertion in between two nodes

    • Insertion the End

    • Delete the First Node of Doubly Linked List

    • Deletion of the Inner Node

    • Delete the Last Node of Doubly Linked List

    • Doubly Linked List Code in Python, Java, C, and C++

    • Doubly Linked List Complexity

    • Doubly Linked List Applications

    • Singly Linked List Vs Doubly Linked List

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